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Podporovan=C3=A9 typy a verzie=
zariaden=C3=AD
Konfigur=C3=A1cia komunika=C4=8Dnej linky
Konfigur=C3=A1cia komunika=C4=8Dnej staniceKonfigur=C3=A1cia meran=C3=BDch =
bodov
Literat=C3=BAra=
Zmeny a =C3=BApravy
<=
a href=3D"#MODBUSDamaticRTU-revizie">Rev=C3=ADzie dokumentu
Komunik=C3=A1cia podporuje =C4=8D=C3=ADtanie =C3=BAdajov z riadiaceho sy= st=C3=A9mu Valmet Damatic prostredn=C3=ADctvom gateway RTU GTW:LIS protokol= om MODBUS verzie RTU.
M=C3=B4=C5=BEu by=C5=A5 zadan=C3=A9 nasledovn=C3=A9 parametre protokolu = stanice:
Tab. =C4=8D. 2
K=C4=BE=C3=BA=C4=8Dov=C3=A9 slovo | Pln=C3=BD n=C3=A1zov | Popis | Jednotka | N=C3=A1hradn=C3=A1 hodnota |
---|---|---|---|---|
RC | Retry Count | Po=C4=8Det opakovan=C3=AD v=C3=BDzvy v pr=C3=ADp= ade chyby komunik=C3=A1cie. | - | 2 |
RT | Retry Timeout | Oneskorenie medzi opakovan=C3=ADm v=C3=BDzvy v p= r=C3=ADpade chyby komunik=C3=A1cie. | ms | 300 milisek. |
WFT | Wait First Timeout | Prv=C3=A9 =C4=8Dakanie na odpove=C4=8F po odosla= n=C3=AD v=C3=BDzvy. | ms | 200 milisek. |
WT | Wait Timeout | Oneskorenie medzi =C4=8D=C3=ADtaniami odpovede d= o jej skompletovania. | ms | 100 milisek. |
MWR | Max Wait Retry | Po=C4=8Det opakovan=C3=AD =C4=8D=C3=ADtania odpo= vede do jej skompletovania. | - | 10 |
String s parametrami protokolu sa zapisuje pod=C4=BEa pravidiel:
K=C4=BE=C3=BA=C4=8Dov=C3=A9_slovo=3Dhodnota;K=C4=BE=C3=BA=C4=8Dov=C3= =A9_slovo=3Dhodnota; ...
Pr=C3=ADklad:
RC=3D1;RT=3D500;
Ak nebolo v inicializa=C4=8Dnom stringu n=C3=A1jden=C3=A9 k=C4=BE=C3=BA= =C4=8Dov=C3=A9 slovo s platnou hodnotou, pou=C5=BEije sa n=C3=A1hradn=C3=A1= hodnota pod=C4=BEa tabu=C4=BEky.
Povolen=C3=A9 typy bodov: Ai, Di
Adresa =E2=80=93 dekadick=C3=A9 =C4=8D=C3=ADslo v rozsahu 0 a=C5= =BE 65535 =E2=80=93 =C4=8D=C3=ADslo MODBUS registra.
=C5=A0tandartne sa =C4=8D=C3=ADtaj=C3=BA 2 byty (znamienkov=C3=BD intege= r) z pr=C3=ADslu=C5=A1n=C3=A9ho registra, typy bodov Ai maj=C3=BA mo=C5=BEn= os=C5=A5 vo=C4=BEby IEE 754, =C4=8Do predstavuje =C4=8D=C3=ADtanie 4= bytov vo form=C3=A1te FLOAT, a to registrov na adres=C3=A1ch Adresa a Adre= sa+1.
Typ bodu Di vy=C5=BEaduje zadanie =C4=8D=C3=ADsla bitu v rozsahu 0 a=C5= =BE 15 =E2=80=93 jeden bit z 16 bitov pre=C4=8D=C3=ADtan=C3=A9ho MODBUS reg= istra.
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S=C3=BAvisiace str=C3=A1nky: